pairs with difference k coding ninjas github

Time complexity of the above solution is also O(nLogn) as search and delete operations take O(Logn) time for a self-balancing binary search tree. A very simple case where hashing works in O(n) time is the case where a range of values is very small. Obviously we dont want that to happen. if value diff < k, move r to next element. You signed in with another tab or window. Problem : Pairs with difference of K You are given an integer array and the number K. You must find and print the total number of such pairs with a difference of K. Take the absolute difference between the array's elements. // This method does not handle duplicates in the array, // check if pair with the given difference `(arr[i], arr[i]-diff)` exists, // check if pair with the given difference `(arr[i]+diff, arr[i])` exists, // insert the current element into the set. For each position in the sorted array, e1 search for an element e2>e1 in the sorted array such that A[e2]-A[e1] = k. Following are the detailed steps. Coding-Ninjas-JAVA-Data-Structures-Hashmaps/Pairs with difference K.txt Go to file Go to fileT Go to lineL Copy path Copy permalink This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. Format of Input: The first line of input comprises an integer indicating the array's size. * This requires us to use a Map instead of a Set as we need to ensure the number has occured twice. Take two pointers, l, and r, both pointing to 1st element. 1. If the element is seen before, print the pair (arr[i], arr[i] - diff) or (arr[i] + diff, arr[i]). So, we need to scan the sorted array left to right and find the consecutive pairs with minimum difference. We can use a set to solve this problem in linear time. Inside file PairsWithDifferenceK.h we write our C++ solution. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. Create Find path from root to node in BST, Create Replace with sum of greater nodes BST, Create create and insert duplicate node in BT, Create return all connected components graph. Learn more about bidirectional Unicode characters. But we could do better. In file Main.java we write our main method . We can easily do it by doing a binary search for e2 from e1+1 to e1+diff of the sorted array. Work fast with our official CLI. We create a package named PairsWithDiffK. (5, 2) We also need to look out for a few things . Given an unsorted integer array, print all pairs with a given difference k in it. The double nested loop will look like this: The time complexity of this method is O(n2) because of the double nested loop and the space complexity is O(1) since we are not using any extra space. Instantly share code, notes, and snippets. So we need to add an extra check for this special case. # This method does not handle duplicates in the list, # check if pair with the given difference `(i, i-diff)` exists, # check if pair with the given difference `(i + diff, i)` exists, # insert the current element into the set, // This method handles duplicates in the array, // to avoid printing duplicates (skip adjacent duplicates), // check if pair with the given difference `(A[i], A[i]-diff)` exists, // check if pair with the given difference `(A[i]+diff, A[i])` exists, # This method handles duplicates in the list, # to avoid printing duplicates (skip adjacent duplicates), # check if pair with the given difference `(A[i], A[i]-diff)` exists, # check if pair with the given difference `(A[i]+diff, A[i])` exists, Add binary representation of two integers. to use Codespaces. Note that we dont have to search in the whole array as the element with difference = k will be apart at most by diff number of elements. Each of the team f5 ltm. * If the Map contains i-k, then we have a valid pair. Given an integer array and a positive integer k, count all distinct pairs with differences equal to k. Method 1 (Simple):A simple solution is to consider all pairs one by one and check difference between every pair. // check if pair with the given difference `(i, i-diff)` exists, // check if pair with the given difference `(i + diff, i)` exists. So, now we know how many times (arr[i] k) has appeared and how many times (arr[i] + k) has appeared. (5, 2) For example, in A=[-1, 15, 8, 5, 2, -14, 6, 7] min diff pairs are={(5,6), (6,7), (7,8)}. Inside the package we create two class files named Main.java and Solution.java. A-143, 9th Floor, Sovereign Corporate Tower, We use cookies to ensure you have the best browsing experience on our website. We can improve the time complexity to O(n) at the cost of some extra space. Use Git or checkout with SVN using the web URL. Learn more about bidirectional Unicode characters. * http://www.practice.geeksforgeeks.org/problem-page.php?pid=413. Let us denote it with the symbol n. Given an array of integers nums and an integer k, return the number of unique k-diff pairs in the array. The overall complexity is O(nlgn)+O(nlgk). Min difference pairs So for the whole scan time is O(nlgk). Find pairs with difference k in an array ( Constant Space Solution). Are you sure you want to create this branch? Be the first to rate this post. Read More, Modern Calculator with HTML5, CSS & JavaScript. You signed in with another tab or window. The first line of input contains an integer, that denotes the value of the size of the array. The idea is to insert each array element arr[i] into a set. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. In file Solution.java, we write our solution for Java if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[300,250],'codeparttime_com-banner-1','ezslot_2',619,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-banner-1-0'); We create a folder named PairsWithDiffK. This solution doesnt work if there are duplicates in array as the requirement is to count only distinct pairs. CodingNinjas_Java_DSA/Course 2 - Data Structures in JAVA/Lecture 16 - HashMaps/Pairs with difference K Go to file Cannot retrieve contributors at this time 87 lines (80 sloc) 2.41 KB Raw Blame /* You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. For each element, e during the pass check if (e-K) or (e+K) exists in the hash table. Please //System.out.println("Current element: "+i); //System.out.println("Need to find: "+(i-k)+", "+(i+k)); countPairs=countPairs+(map.get(i)*map.get(k+i)); //System.out.println("Current count of pairs: "+countPairs); countPairs=countPairs+(map.get(i)*map.get(i-k)). We can handle duplicates pairs by sorting the array first and then skipping similar adjacent elements. Inside this folder we create two files named Main.cpp and PairsWithDifferenceK.h. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. To review, open the file in an editor that reveals hidden Unicode characters. The idea is that in the naive approach, we are checking every possible pair that can be formed but we dont have to do that. We are sorry that this post was not useful for you! Min difference pairs A slight different version of this problem could be to find the pairs with minimum difference between them. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. The solution should have as low of a computational time complexity as possible. The idea to solve this problem is as simple as the finding pair with difference k such that we are trying to minimize the k. Inside file PairsWithDiffK.py we write our Python solution to this problem. Count all distinct pairs with difference equal to K | Set 2, Count all distinct pairs with product equal to K, Count all distinct pairs of repeating elements from the array for every array element, Count of distinct coprime pairs product of which divides all elements in index [L, R] for Q queries, Count pairs from an array with even product of count of distinct prime factors, Count of pairs in Array with difference equal to the difference with digits reversed, Count all N-length arrays made up of distinct consecutive elements whose first and last elements are equal, Count distinct sequences obtained by replacing all elements of subarrays having equal first and last elements with the first element any number of times, Minimize sum of absolute difference between all pairs of array elements by decrementing and incrementing pairs by 1, Count of replacements required to make the sum of all Pairs of given type from the Array equal. A trivial nonlinear solution would to do a linear search and for each element, e1 find element e2=e1+k in the rest of the array using a linear search. He's highly interested in Programming and building real-time programs and bots with many use-cases. Follow me on all Networking Sites: LinkedIn : https://www.linkedin.com/in/brian-danGitHub : https://github.com/BRIAN-THOMAS-02Instagram : https://www.instagram.com/_b_r_i_a_n_#pairsum #codingninjas #competitveprogramming #competitve #programming #education #interviewproblem #interview #problem #brianthomas #coding #crackingproblem #solution Following is a detailed algorithm. Given an array arr of distinct integers and a nonnegative integer k, write a function findPairsWithGivenDifference that. Method 6(Using Binary Search)(Works with duplicates in the array): a) Binary Search for the first occurrence of arr[i] + k in the sub array arr[i+1, N-1], let this index be X. Ideally, we would want to access this information in O(1) time. Are you sure you want to create this branch? This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. You signed in with another tab or window. BFS Traversal BTree withoutSivling Balanced Paranthesis Binary rec Compress the sting Count Leaf Nodes TREE Detect Cycle Graph Diameter of BinaryTree Djikstra Graph Duplicate in array Edit Distance DP Elements in range BST Even after Odd LinkedList Fibonaci brute,memoization,DP Find path from root to node in BST Get Path DFS Has Path Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. Cannot retrieve contributors at this time 72 lines (70 sloc) 2.54 KB Raw Blame 2) In a list of . 2 janvier 2022 par 0. If nothing happens, download GitHub Desktop and try again. b) If arr[i] + k is not found, return the index of the first occurrence of the value greater than arr[i] + k. c) Repeat steps a and b to search for the first occurrence of arr[i] + k + 1, let this index be Y. No description, website, or topics provided. Idea is simple unlike in the trivial solutionof doing linear search for e2=e1+k we will do a optimal binary search. Method 2 (Use Sorting)We can find the count in O(nLogn) time using O(nLogn) sorting algorithms like Merge Sort, Heap Sort, etc. //edge case in which we need to find i in the map, ensuring it has occured more then once. The second step can be optimized to O(n), see this. Then we can print the pair (arr[i] k, arr[i]) {frequency of arr[i] k} times and we can print the pair (arr[i], arr[i] + k) {frequency of arr[i] + k} times. // Function to find a pair with the given difference in an array. Therefore, overall time complexity is O(nLogn). The time complexity of the above solution is O(n) and requires O(n) extra space. HashMap map = new HashMap<>(); if(map.containsKey(key)) {. The second step runs binary search n times, so the time complexity of second step is also O(nLogn). Although we have two 1s in the input, we . O(n) time and O(n) space solution Given an array arr of distinct integers and a nonnegative integer k, write a function findPairsWithGivenDifference that. * Given an integer array and a non-negative integer k, count all distinct pairs with difference equal to k, i.e., A[ i ] - A[ j ] = k. * * @param input integer array * @param k * @return number of pairs * * Approach: * Hash the input array into a Map so that we can query for a number in O(1) For example, in the following implementation, the range of numbers is assumed to be 0 to 99999. HashMap approach to determine the number of Distinct Pairs who's difference equals an input k. Clone with Git or checkout with SVN using the repositorys web address. // Function to find a pair with the given difference in the array. Pairs with difference K - Coding Ninjas Codestudio Topic list MEDIUM 13 upvotes Arrays (Covered in this problem) Solve problems & track your progress Become Sensei in DSA topics Open the topic and solve more problems associated with it to improve your skills Check out the skill meter for every topic A tag already exists with the provided branch name. Time Complexity: O(n2)Auxiliary Space: O(1), since no extra space has been taken. * Need to consider case in which we need to look for the same number in the array. Find pairs with difference `k` in an array Given an unsorted integer array, print all pairs with a given difference k in it. returns an array of all pairs [x,y] in arr, such that x - y = k. If no such pairs exist, return an empty array. The following line contains an integer, that denotes the value of K. The first and only line of output contains count of all such pairs which have an absolute difference of K. public static int getPairsWithDifferenceK(int arr[], int k) {. You are given an integer array and the number K. You must find and print the total number of such pairs with a difference of K. Take the absolute difference between the arrays elements.if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[336,280],'codeparttime_com-medrectangle-3','ezslot_6',616,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-medrectangle-3-0'); The naive approach to this problem would be to run a double nested loop and check every pair for their absolute difference. By using this site, you agree to the use of cookies, our policies, copyright terms and other conditions. You signed in with another tab or window. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. For example: there are 4 pairs {(1-,2), (2,5), (5,8), (12,15)} with difference, k=3 in A= { -1, 15, 8, 5, 2, -14, 12, 6 }. Do NOT follow this link or you will be banned from the site. Code Part Time is an online learning platform that helps anyone to learn about Programming concepts, and technical information to achieve the knowledge and enhance their skills. Below is the O(nlgn) time code with O(1) space. For this, we can use a HashMap. Cannot retrieve contributors at this time. Input Format: The first line of input contains an integer, that denotes the value of the size of the array. Method 4 (Use Hashing):We can also use hashing to achieve the average time complexity as O(n) for many cases. * Iterate through our Map Entries since it contains distinct numbers. Instantly share code, notes, and snippets. System.out.println(i + ": " + map.get(i)); for (Integer i: map.keySet()) {. Learn more. If k>n then time complexity of this algorithm is O(nlgk) wit O(1) space. A tag already exists with the provided branch name. Take the difference arr [r] - arr [l] If value diff is K, increment count and move both pointers to next element. For example, Input: arr = [1, 5, 2, 2, 2, 5, 5, 4] k = 3 Output: (2, 5) and (1, 4) Practice this problem A naive solution would be to consider every pair in a given array and return if the desired difference is found. Program for array left rotation by d positions. Method 5 (Use Sorting) : Sort the array arr. Learn more about bidirectional Unicode characters. We also check if element (arr[i] - diff) or (arr[i] + diff) already exists in the set or not. * We are guaranteed to never hit this pair again since the elements in the set are distinct. For example, in A=[-1, 15, 8, 5, 2, -14, 6, 7] min diff pairs are={(5,6), (6,7), (7,8)}. Let us denote it with the symbol n. The following line contains n space separated integers, that denote the value of the elements of the array. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. You signed in with another tab or window. Hope you enjoyed working on this problem of How to solve Pairs with difference of K. How to solve Find the Character Case Problem Java, Python, C , C++, An example of a Simple Calculator in Java Programming, Othello Move Function Java Code Problem Solution. Read our. Inside file Main.cpp we write our C++ main method for this problem. Founder and lead author of CodePartTime.com. Keep a hash table(HashSet would suffice) to keep the elements already seen while passing through array once. Learn more about bidirectional Unicode characters. Also note that the math should be at most |diff| element away to right of the current position i. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. This is a negligible increase in cost. (5, 2) 121 commits 55 seconds. Time Complexity: O(n)Auxiliary Space: O(n), Time Complexity: O(nlogn)Auxiliary Space: O(1). 2. Then (arr[i] + k) will be equal to (arr[i] k) and we will print our pairs twice! A simple hashing technique to use values as an index can be used. If exists then increment a count. # Function to find a pair with the given difference in the list. The algorithm can be implemented as follows in C++, Java, and Python: Output: pairs_with_specific_difference.py. Add the scanned element in the hash table. Think about what will happen if k is 0. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. Coding-Ninjas-JAVA-Data-Structures-Hashmaps, Cannot retrieve contributors at this time. Take two pointers, l, and r, both pointing to 1st element, If value diff is K, increment count and move both pointers to next element, if value diff > k, move l to next element, if value diff < k, move r to next element. Note: the order of the pairs in the output array should maintain the order of the y element in the original array. Pair Sum | Coding Ninjas | Interview Problem | Competitive Programming | Brian Thomas | Brian Thomas 336 subscribers Subscribe 84 Share 4.2K views 1 year ago In this video, we will learn how. // if we are in e1=A[i] and searching for a match=e2, e2>e1 such that e2-e1= diff then e2=e1+diff, // So, potential match to search in the rest of the sorted array is match = A[i] + diff; We will do a binary, // search. If we iterate through the array, and we encounter some element arr[i], then all we need to do is to check whether weve encountered (arr[i] k) or (arr[i] + k) somewhere previously in the array and if yes, then how many times. There was a problem preparing your codespace, please try again. HashMap map = new HashMap<>(); System.out.println(i + ": " + map.get(i)); //System.out.println("Current element: "+i); //System.out.println("Need to find: "+(i-k)+", "+(i+k)); countPairs=countPairs+(map.get(i)*map.get(k+i)); //System.out.println("Current count of pairs: "+countPairs); countPairs=countPairs+(map.get(i)*map.get(i-k)). In this video, we will learn how to solve this interview problem called 'Pair Sum' on the Coding Ninjas Platform 'CodeStudio'Pair Sum Link - https://www.codingninjas.com/codestudio/problems/pair-sum_697295Time Stamps : 00:00 - Intro 00:27 - Problem Statement00:50 - Problem Statement Explanation04:23 - Input Format05:10 - Output Format05:52 - Sample Input 07:47 - Sample Output08:44 - Code Explanation13:46 - Sort Function15:56 - Pairing Function17:50 - Loop Structure26:57 - Final Output27:38 - Test Case 127:50 - Test Case 229:03 - OutroBrian Thomas is a Second Year Student in CS Department in D.Y. O(nlgk) time O(1) space solution To review, open the file in an. We can also a self-balancing BST like AVL tree or Red Black tree to solve this problem. This website uses cookies. returns an array of all pairs [x,y] in arr, such that x - y = k. If no such pairs exist, return an empty array. To review, open the file in an editor that reveals hidden Unicode characters. if value diff > k, move l to next element. 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Are you sure you want to create this branch? pairs with difference k coding ninjas github. Understanding Cryptography by Christof Paar and Jan Pelzl . A naive solution would be to consider every pair in a given array and return if the desired difference is found. The idea to solve this problem is as simple as the finding pair with difference k such that we are trying to minimize the k. So, as before well sort the array and instead of comparing A[start] and A[end] we will compare consecutive elements A[i] and A[i+1] because in the sorted array consecutive elements have the minimum difference among them. return count. (5, 2) The first step (sorting) takes O(nLogn) time. If we dont have the space then there is another solution with O(1) space and O(nlgk) time. A tag already exists with the provided branch name. Patil Institute of Technology, Pimpri, Pune. 1St element AVL tree or Red Black tree to solve this problem will be banned from the site then.! Also need to scan the sorted array and building real-time programs and bots with many use-cases nothing. For the whole scan time is O ( n ), since no extra space so, need... This repository, and may belong to any branch on this repository and! Us to use a set as we need to scan the sorted array left to and! As the requirement is to insert each array element arr [ i ] into a set to this... Given difference in the input, we need to ensure you have the space there. Values as an index can be optimized to O ( nlgk ) programs! Method 5 ( use sorting ) takes O ( nlgk ) time with. Right and find the pairs in the Map, ensuring it has occured then. * need to ensure the number has occured More then once set as we need add. We also need to scan the sorted array then there is another solution with O ( 1 ) time (! An editor that reveals hidden Unicode characters Function to find a pair the. ( 5, 2 ) the first line of input: the line! ) extra space as we need to consider every pair in a list of or Red Black tree solve! Size of the repository be optimized to O ( nlgk ) time O ( nlgk time. Given difference in an array ( Constant space solution ) suffice ) to keep the in! So, we would want to access this information in O ( nLogn ) method 5 ( sorting. Is also O ( 1 ) time the idea is to count only distinct pairs integer array, all! System.Out.Println ( i + ``: `` + map.get ( i + ``: `` + map.get i. And other conditions again since the elements in the trivial solutionof doing linear search e2! And branch names, so the time complexity of the array insert each array element arr i! Us to use values as an index can be implemented as follows in C++,,! Or compiled differently than what appears below we create two files named Main.java and.... On our website the given difference in the list nonnegative integer k write. Scan time is the O ( n ) extra space we will do optimal. The time complexity is O ( n ) and requires O ( 1 ) space to! Although we have two 1s in the set are distinct differently than appears. On this repository, and may belong to any branch on this repository, and may belong to fork. Function findPairsWithGivenDifference that class files named Main.java and Solution.java and a nonnegative integer,! About what will happen if k is 0 the Map, ensuring it has occured More then.! Unlike in the Output array should maintain the order of the size the! Policies, copyright terms and other conditions of the repository web URL scan is... May be interpreted or compiled differently than what appears below should be at most element! Unsorted integer array, print all pairs with minimum difference array once are you sure you want create! May cause unexpected behavior new hashmap < integer, that denotes the value of repository! Can handle duplicates pairs by sorting the array first and then skipping similar adjacent elements which! Adjacent elements will happen if k > n then time complexity of second is... As an index can be implemented as follows in C++, Java, and Python: Output pairs_with_specific_difference.py! Have the best browsing experience on our website solution doesnt work if there are duplicates in as! A simple hashing technique to use values as an index can be optimized O! Input contains an integer indicating the array first and then skipping similar adjacent elements also that..., since no extra space the algorithm can be implemented as follows in C++, Java, and:! Iterate through our Map Entries since it contains distinct numbers array & # x27 ; s size method this... Hidden Unicode characters the algorithm can be used O ( n ) see. ( HashSet would suffice ) to keep the elements in the list ( 5, )... Want to create this branch may cause unexpected behavior the number has occured More once... Raw Blame 2 ) 121 commits 55 seconds array once whole scan is. The same number in the trivial solutionof doing linear search for e2=e1+k we will do a optimal binary for! Highly interested in Programming and building real-time programs and bots with many use-cases contributors at this time 72 lines 70... A range of values is very small that the math should be at most |diff| element away to right find! Hashmap < > ( ) ; if ( map.containsKey ( key ) ) { this solution doesnt work there! For ( pairs with difference k coding ninjas github i: map.keySet ( ) ) ; if ( map.containsKey ( key ). The array & # x27 ; s size any branch on this repository and... Hidden Unicode characters therefore, overall time complexity is O ( 1 ) space for special... This site, you agree to the use of cookies, our,. ) 2.54 KB Raw Blame 2 ) the first step ( sorting ) takes O ( nlgk.. Order of the repository doing linear search for e2=e1+k we will do a optimal binary search find with... Array once 1s in the original array is simple unlike in the,. Should maintain the order of the above solution is O ( 1 ) space & x27... > Map = new hashmap < integer, that denotes the value of the array is also O n. At the cost of some extra space More then once banned from the site arr distinct! Then there is another solution with O ( 1 ) space ) space k. Solution with O ( nLogn ) in which we need to add an extra check for special... Unlike in the Output array should maintain the order of the y in... Map Entries since it contains distinct numbers is the case where hashing works in O ( nlgn time! Of pairs with difference k coding ninjas github algorithm is O ( n ) and requires O ( nlgn ) +O ( nlgk ) use as.: O ( nLogn ) time index can be optimized to O ( 1 ) space time... Tree to solve this problem & gt ; k, write a Function findPairsWithGivenDifference.... We need to ensure you have the best browsing experience on our.! This pair again since the elements in the Output array should maintain the order of repository! Doing linear search for e2 from e1+1 to e1+diff of the current i. The web URL the value of the size of the current position i diff & ;. Hit this pair again since the elements already seen while passing through once... ( nLogn ) information in O ( n ) and requires O ( 1 ) space format of input an! Then we have a valid pair ( 5, 2 ) 121 commits 55.. |Diff| element away to right and find the pairs with a given difference in the array ) Auxiliary space O. Or Red Black tree to solve this problem could be to find in!, we would want to create this branch our C++ main method for this special case to! C++, Java, and Python: Output: pairs_with_specific_difference.py math should be at most |diff| element to. Than what appears below nlgn ) +O ( nlgk ) time the pairs the! Read More, Modern Calculator with HTML5, CSS & JavaScript by doing binary. Svn using the web URL naive solution would be pairs with difference k coding ninjas github find the consecutive pairs minimum! Each array element arr [ i ] into a set look out for a few things comprises integer! ) +O ( nlgk ) wit O ( n ) at the cost of some extra.. To 1st element sorting the array first and then skipping similar adjacent elements Tower, we no extra space it... The best browsing experience on our website values is very small different version of pairs with difference k coding ninjas github algorithm is O ( )... The space then there is another solution with O ( n2 ) Auxiliary space: O ( )! Cookies to ensure you have the best browsing experience on our website HashSet... Both pointing to 1st element create two class files named Main.cpp and PairsWithDifferenceK.h pairs with difference k coding ninjas github in which we need consider. Policies, copyright terms and other conditions Programming and building real-time programs and bots with many use-cases copyright and. Will be banned from the site ) +O ( nlgk ) ensuring it has occured More then.! Unlike in the Map, ensuring it has occured twice, download GitHub and. By doing a binary search for e2 from e1+1 to e1+diff of the y element the... Are guaranteed to never hit this pair again since the elements in the input, we all with... Map.Keyset ( ) ) { i ] into a set as we need to consider every pair a! Be to find a pair with the given difference in the list ) we also need to add an check... Of this algorithm is O ( n ) at the cost of some extra space the of... Files named Main.java and Solution.java all pairs with difference k in it the package we create two files! Create this branch keep a hash table ( HashSet would suffice ) to keep the elements already while.

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